Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)

Published by Pearson
ISBN 10: 0-32193-104-1
ISBN 13: 978-0-32193-104-7

Chapter 1 - Functions and Their Graphs - Section 1.1 Functions - 1.1 Assess Your Understanding - Page 54: 59


The domain is $\{x\in \mathbb{R}|x\gt1\}$.

Work Step by Step

Requirement (1) For a fraction to be defined, the denominator can not be equal to $0$. Thus, $x-1\ne0$ $x\ne1$ Requirement (2) For a square root to be defined, the expression inside the radical must be greater than or equal to $0$. Thus, $\frac{2}{x-1}\geq0$ As the nominator will always be positive, the denominator should also be positive. $x-1\gt 0$ $x\gt1$ The two requirements can be applied together, to define the domain: $x\gt1$ and $x\ne1$. Therefore the domain is {$x|x\gt1$}.
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.