Answer
$\{x|x\ne-9, 4\}$, $\frac{1}{8}$
Work Step by Step
Step 1. The domain requirement for $h(x)=\frac{x-4}{x^2+5x-36}=\frac{x-4}{(x+9)(x-4)}=\frac{1}{x+9}$ is $(x+9)(x-4)\ne0$ or $\{x|x\ne-9, 4\}$
Step 2. $h(-1)=\frac{1}{-1+9}=\frac{1}{8}$
Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)
by Sullivan III, Michael
Published by
Pearson
ISBN 10:
0-32193-104-1
ISBN 13:
978-0-32193-104-7
Chapter 1 - Functions and Their Graphs - Chapter Test - Page 115: 4
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