Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)

Published by Pearson
ISBN 10: 0-32193-104-1
ISBN 13: 978-0-32193-104-7

Chapter 1 - Functions and Their Graphs - Chapter Test - Page 115: 3

Answer

$\{x|x\ne-2\}$, $1$

Work Step by Step

Step 1. The domain requirement for $g(x)=\frac{x+2}{|x+2|}$ is $x+2\ne0$ or $\{x|x\ne-2\}$ Step 2. $g(-1)=\frac{-1+2}{|-1+2|}=1$
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