#### Answer

The function is neither even nor odd.

#### Work Step by Step

Remember that when a function is odd, then $g(−x)=−g(x)$ and when a function is even, then $g(−x)=g(x)$.
Thus, in order to find out whether the function is even, odd, or neither, we will find $g(-x)$ .
We are given: $g(x)=1-x+x^3$
Thus we have:
$g(-x)=1-(-x)+(-x)^3\\=1+x-x^3$
This shows that the function is neither even nor odd.