Answer
$ \frac{1}{3}(x^2+4)^{1/3}(11x^2+12)$
Work Step by Step
$(x^2+4)^{4/3}+x\cdot\frac{4}{3}(x^2+4)^{1/3}\cdot2x=\frac{1}{3}(x^2+4)^{1/3}(3x^2+12+8x^2)=\frac{1}{3}(x^2+4)^{1/3}(11x^2+12)$
Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)
by Sullivan III, Michael
Published by
Pearson
ISBN 10:
0-32193-104-1
ISBN 13:
978-0-32193-104-7
Appendix A - Review - A.7 nth Roots; Rational Exponents - A.7 Assess Your Understanding - Page A62: 90
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