Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)

Published by Pearson
ISBN 10: 0-32193-104-1
ISBN 13: 978-0-32193-104-7

Appendix A - Review - A.7 nth Roots; Rational Exponents - A.7 Assess Your Understanding - Page A62: 109


$ T=2 \sqrt{ 2} \pi\ sec= 8.89\ sec .$

Work Step by Step

The period $T$ of a pendulum is given by $$ T=2\pi\sqrt{\frac{l}{32}}=2\pi\sqrt{\frac{64}{32}}=2 \sqrt{ 2} \pi\ sec .$$ Thus, we have: $$ T=2 \sqrt{ 2} \pi\ sec= 8.89\ sec .$$
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