Precalculus (6th Edition)

Published by Pearson
ISBN 10: 013421742X
ISBN 13: 978-0-13421-742-0

Chapter R - Review of Basic Concepts - Test - Page 86: 30

Answer

$ \frac{9}{16}$

Work Step by Step

$(-\frac{64}{27})^{-2/3}=(-\frac{4^3}{3^3})^{-2/3}=(-\frac{4}{3})^{-2}=(-\frac{3}{4})^{2}=\frac{9}{16}$
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