Precalculus (6th Edition)

Published by Pearson
ISBN 10: 013421742X
ISBN 13: 978-0-13421-742-0

Chapter R - Review of Basic Concepts - Test - Page 86: 28

Answer

$ \frac{7(\sqrt {11}+\sqrt 7)}{2}$

Work Step by Step

$\frac{14}{\sqrt {11}-\sqrt 7}=\frac{14}{\sqrt {11}-\sqrt 7}\times\frac{\sqrt {11}+\sqrt 7}{\sqrt {11}+\sqrt 7}=\frac{14(\sqrt {11}+\sqrt 7)}{11-7}=\frac{7(\sqrt {11}+\sqrt 7)}{2}$
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