Answer
$\frac{2x(1-3x^2)}{(x^2+1)^5}$
Work Step by Step
Start with cancelling the common factor $(x^2+1)^3$, we have:
$\frac{(x^2+1)^4(2x)-x^2(4)(x^2+1)^3(2x)}{(x^2+1)^8}=\frac{(x^2+1)(2x)-x^2(4)(2x)}{(x^2+1)^5}=\frac{2x(1-3x^2)}{(x^2+1)^5}$
Precalculus (6th Edition)
by Lial, Margaret L.; Hornsby, John; Schneider, David I.; Daniels, Callie
Published by
Pearson
ISBN 10:
013421742X
ISBN 13:
978-0-13421-742-0
Chapter R - Review of Basic Concepts - R.6 Rational Exponents - R.6 Exercises - Page 65: 111
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