Precalculus (6th Edition)

Published by Pearson
ISBN 10: 013421742X
ISBN 13: 978-0-13421-742-0

Chapter R - Review of Basic Concepts - R.6 Rational Exponents - R.6 Exercises - Page 65: 109

Answer

$\frac{y(xy-9)}{x^2y^2-9}$

Work Step by Step

Multiply $\frac{y^2}{y^2}$ to the expression, we have: $\frac{x-9y^{-1}}{(x-3y^{-1})(x+3y^{-1})}=\frac{y^2}{y^2}\cdot\frac{x-9y^{-1}}{(x-3y^{-1})(x+3y^{-1})}=\frac{y(xy-9)}{(xy-3)(xy+3)}=\frac{y(xy-9)}{x^2y^2-9}$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.