Precalculus (6th Edition)

Published by Pearson
ISBN 10: 013421742X
ISBN 13: 978-0-13421-742-0

Chapter R - Review of Basic Concepts - R.2 Real Numbers and Their Properties - R.2 Exercises - Page 21: 97



Work Step by Step

Evaluate the given expression by substituting the given values of $x$ and $y$ to obtain: $=\dfrac{|-8(2)+(-4)}{-|-4|} \\=\dfrac{|-16+(-4)}{-(4)} \\=\dfrac{|-20|}{-4} \\=\dfrac{20}{-4} \\=-5$
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