Precalculus (6th Edition)

Published by Pearson
ISBN 10: 013421742X
ISBN 13: 978-0-13421-742-0

Chapter R - Review of Basic Concepts - R.2 Real Numbers and Their Properties - R.2 Exercises - Page 21: 95



Work Step by Step

Evaluate the given expression by substituting the given values of $x$ and $y$ to obtain: $=\dfrac{2|2| - 3|-4|}{|-4(2)|} \\=\dfrac{2(2)-3(4)}{|-8|} \\=\dfrac{4-12}{8} \\=\dfrac{-8}{8} \\=-1$
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