Answer
$\begin{bmatrix} -\dfrac{1}{4} & \dfrac{1}{6}\\ 0& \dfrac{1}{3} \end{bmatrix} $
Work Step by Step
Our aim is to find inverse of the given matrix.
$A= \begin{bmatrix} -4 & 2\\ 0& 3 \end{bmatrix} =-4 (3)-0=-12$
Now, $A^{-1}=\dfrac{adj A}{|A|}=\dfrac{1}{-12}\begin{bmatrix} 3 & -2\\ 0& -4 \end{bmatrix}=\begin{bmatrix} -\dfrac{1}{4} & \dfrac{1}{6}\\ 0& \dfrac{1}{3} \end{bmatrix} $
