Precalculus (6th Edition)

Published by Pearson
ISBN 10: 013421742X
ISBN 13: 978-0-13421-742-0

Chapter 9 - Systems and Matrices - 9.5 Nonlinear Systems of Equations - 9.5 Exercises - Page 902: 3

Answer

$$\left( { - 1,3} \right)$$

Work Step by Step

$$\eqalign{ & \,2x + y = 1\,\,\,\,\,\,\,\,\,\left( {\bf{1}} \right) \cr & {x^2} + {y^2} = 10\,\,\,\,\,\,\left( {\bf{2}} \right) \cr & \cr & {\text{We know the point }}\left( {x,3} \right),{\text{ then }}y = 3 \cr & {\text{Substitute }}y = 3{\text{ into the equation }}\left( {\bf{1}} \right){\text{ and solve for }}x \cr & \,2x + 3 = 1 \cr & \,2x = - 2 \cr & x = - 1 \cr & \cr & {\text{Therefore, one of the solutions onf the nonlinear systems is }} \cr & \left( { - 1,3} \right) \cr} $$
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