Precalculus (6th Edition)

Published by Pearson
ISBN 10: 013421742X
ISBN 13: 978-0-13421-742-0

Chapter 9 - Systems and Matrices - 9.5 Nonlinear Systems of Equations - 9.5 Exercises - Page 902: 2

Answer

$$\left( {2,10} \right)$$

Work Step by Step

$$\eqalign{ & \,\,\,\,\,\,\,\,\,\,\,\,y = {x^2} + 6\,\,\,\,\,\left( {\bf{1}} \right) \cr & {x^2} - {y^2} = - 96\,\,\,\,\,\,\,\,\,\left( {\bf{2}} \right) \cr & \cr & {\text{We know the point }}\left( {2,y} \right),{\text{ then }}x = 2 \cr & {\text{Substitute }}x = 2{\text{ into the equation }}\left( {\bf{1}} \right){\text{ to find the value of }}y \cr & y = {\left( 2 \right)^2} + 6 \cr & y = 10 \cr & \cr & {\text{Therefore, one of the solutions onf the nonlinear systems is }} \cr & \left( {2,10} \right) \cr} $$
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