Precalculus (6th Edition)

Published by Pearson
ISBN 10: 013421742X
ISBN 13: 978-0-13421-742-0

Chapter 9 - Systems and Matrices - 9.3 Determinant Solution of Linear Systems - 9.3 Exercises - Page 885: 34

Answer

$$ - 1$$

Work Step by Step

$$\eqalign{ & \left| {\matrix{ 0 & 0 & { - 1} \cr { - 1} & 0 & 1 \cr 0 & { - 1} & 0 \cr } } \right| \cr & {\rm{Calculating\, the \,determinant\, by \,expanding \,the \,third \,row}} \cr & \left| {\matrix{ 0 & 0 & { - 1} \cr { - 1} & 0 & 1 \cr 0 & { - 1} & 0 \cr } } \right| = 0\left| {\matrix{ 0 & { - 1} \cr 0 & 1 \cr } } \right| - \left( { - 1} \right)\left| {\matrix{ 0 & { - 1} \cr { - 1} & 1 \cr } } \right| + 0\left| {\matrix{ 0 & 0 \cr { - 1} & 0 \cr } } \right| \cr & {\rm{Solving}} \cr & \left| {\matrix{ 0 & 0 & { - 1} \cr { - 1} & 0 & 1 \cr 0 & { - 1} & 0 \cr } } \right| = 0 + \left( {0 - 1} \right) + 0 \cr & {\rm{Simplifying}} \cr & \left| {\matrix{ 0 & 0 & { - 1} \cr { - 1} & 0 & 1 \cr 0 & { - 1} & 0 \cr } } \right| = - 1 \cr} $$
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