Answer
$1.91\ mi$
Work Step by Step
1. See figure, based on the bearing conditions, we have angle $A=90-48=42^\circ, B=90-(360-302)=90-58=32^\circ, C=180-42-32=106^\circ$
2. Use the Law of Sines, we have $\frac{sinB}{AC}=\frac{sinC}{3.46}$, thus $AC=\frac{3.46sin32^\circ}{sin106^\circ}\approx1.91\ mi$
