Precalculus (6th Edition)

Published by Pearson
ISBN 10: 013421742X
ISBN 13: 978-0-13421-742-0

Chapter 8 - Application of Trigonometry - Chapter 8 Test Prep - Review Exercises - Page 842: 97

Answer

$$r = \frac{4}{{\cos \theta + 2\sin \theta }}$$

Work Step by Step

$$\eqalign{ & x + 2y = 4 \cr & {\text{Use }}r\sin \theta = y{\text{ and }}r\cos \theta = x,{\text{ then}} \cr & r\cos \theta + 2r\sin \theta = 4 \cr & {\text{factor and solve for }}r \cr & r\left( {\cos \theta + 2\sin \theta } \right) = 4 \cr & r = \frac{4}{{\cos \theta + 2\sin \theta }} \cr} $$
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