Chapter 8 - Application of Trigonometry - Chapter 8 Test Prep - Review Exercises - Page 842: 92

$$\tan \theta = 1$$

$$\eqalign{ & y = x \cr & {\text{Use }}r\sin \theta = y{\text{ and }}r\cos \theta = x,{\text{ then}} \cr & r\sin \theta = r\cos \theta \cr & \sin \theta = \cos \theta \cr & {\text{Divide both sides by cos}}\theta \cr & \frac{{\sin \theta }}{{\cos \theta }} = \frac{{\cos \theta }}{{\cos \theta }} \cr & \tan \theta = 1 \cr} $$