Precalculus (6th Edition)

Published by Pearson
ISBN 10: 013421742X
ISBN 13: 978-0-13421-742-0

Chapter 7 - Trigonometric Identities and Equations - Test - Page 741: 21

Answer

$90^\circ, 270^\circ$

Work Step by Step

1. Use the identify $sin^2\theta+cos^2\theta=1$, we have $1-cos^2\theta=cos^2\theta +1$, thus $cos^2\theta=0$ and $cos\theta=0$ 2. For $\theta\in[0^\circ,360^\circ)$, we can find $\theta=90^\circ, 270^\circ$
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