Precalculus (6th Edition)

Published by Pearson
ISBN 10: 013421742X
ISBN 13: 978-0-13421-742-0

Chapter 7 - Trigonometric Identities and Equations - Test - Page 741: 20

Answer

$30^\circ, 330^\circ$

Work Step by Step

1. From the given equation $-3sec\theta+2\sqrt 3=0$, we have $sec\theta=\frac{2\sqrt 3}{3}$ and $cos\theta=\frac{1}{sec\theta}=\frac{\sqrt 3}{2}$ 2. For $\theta\in[0^\circ,360^\circ)$, we can find $\theta=30^\circ, 330^\circ$
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