Answer
$\sin 4x=4\sin x\cos x\cos 2x$
Work Step by Step
Start with the left side:
$\sin 4x$
Rewrite $\sin 4x$ as $\sin (2*2x)$ and use the double-angle identity:
$=\sin (2*2x)$
$=2\sin 2x\cos 2x$
Use the double-angle identity again:
$=2(2\sin x\cos x)\cos 2x$
$=4\sin x\cos x\cos 2x$