#### Answer

$\tan 4\theta$

#### Work Step by Step

Comparing with the Half-Angle Identity
$\displaystyle \tan\frac{A}{2}=\pm\sqrt{\frac{1-\cos A}{1+\cos A}}$,
if we define $ A=8\theta$,
the RHS equals the given expression.
So, the LHS =$ \tan 4\theta$

Published by
Pearson

ISBN 10:
013421742X

ISBN 13:
978-0-13421-742-0

$\tan 4\theta$

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