Precalculus (6th Edition)

Published by Pearson
ISBN 10: 013421742X
ISBN 13: 978-0-13421-742-0

Chapter 7 - Trigonometric Identities and Equations - 7.4 Double-Angle and Half-Angle Identities - 7.4 Exercises - Page 694: 75

Answer

$\tan 4\theta$

Work Step by Step

Comparing with the Half-Angle Identity $\displaystyle \tan\frac{A}{2}=\pm\sqrt{\frac{1-\cos A}{1+\cos A}}$, if we define $ A=8\theta$, the RHS equals the given expression. So, the LHS =$ \tan 4\theta$
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