#### Answer

$2\cos 98.5^{o}\cdot\sin 3.5^{o}$

#### Work Step by Step

Sum-to-Product:
$\displaystyle \sin A-\sin B=2\cos(\frac{A+B}{2})\sin(\frac{A-B}{2})$
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$\displaystyle \frac{A+B}{2}=\frac{102^{o}+95^{o}}{2}=98.5^{o}$
$\displaystyle \frac{A-B}{2}=\frac{102^{o}-95^{o}}{2}=3.5^{o}$
$\sin 102^{o}-\sin95^{o}=2\cos 98.5^{o}\cdot\sin 3.5^{o}$