Precalculus (6th Edition)

Published by Pearson
ISBN 10: 013421742X
ISBN 13: 978-0-13421-742-0

Chapter 7 - Trigonometric Identities and Equations - 7.4 Double-Angle and Half-Angle Identities - 7.4 Exercises: 30

Answer

$=\dfrac {1}{16}\sin 59^{0}$

Work Step by Step

$2\sin \alpha \cos \alpha =\sin 2\alpha \Rightarrow \dfrac {1}{8}\sin 29.5\cos 29.5=\dfrac {1}{16}\left( 2\sin 29.5\cos 29.5\right) =\dfrac {1}{16}\sin (2\times 29.5=\dfrac {1}{16}\sin 59^{0}$
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