#### Answer

$=\dfrac {1}{16}\sin 59^{0}$

#### Work Step by Step

$2\sin \alpha \cos \alpha =\sin 2\alpha \Rightarrow \dfrac {1}{8}\sin 29.5\cos 29.5=\dfrac {1}{16}\left( 2\sin 29.5\cos 29.5\right) =\dfrac {1}{16}\sin (2\times 29.5=\dfrac {1}{16}\sin 59^{0}$