Precalculus (6th Edition)

Published by Pearson
ISBN 10: 013421742X
ISBN 13: 978-0-13421-742-0

Chapter 7 - Trigonometric Identities and Equations - 7.1 Fundamental Identities - 7.1 Exercises - Page 658: 32

Answer

$tan\theta=\sqrt 3$ $sin \theta=\frac{\sqrt 3}{2}$ $sec\theta=2$ $csc\theta=\frac{2\sqrt 3}{3}$ $cot\theta==\frac{\sqrt 3}{3}$

Work Step by Step

$ cos\theta=1/2$ I quadrant All other five trig functions are positive beacause cos is in the I quadrant $sin \theta=\sqrt {1-(\frac{1}{2}^{2})} $ Use the trig identity $cos \theta^2+sin \theta^2=1$ $sin \theta=\sqrt {1-\frac{1}{4}} =\sqrt \frac{3}{4}=\frac{\sqrt 3}{2}$ $tan\theta=\frac{sin\theta}{cos\theta}=\sqrt 3$ $sec\theta=\frac{1}{cos\theta}=2$ $csc\theta=\frac{1}{sin\theta}=\frac{2}{\sqrt 3}=\frac{2}{\sqrt 3}\frac{\sqrt 3}{\sqrt 3}=\frac{2\sqrt 3}{3}$ $cot\theta=\frac{1}{tan\theta}=\frac{1}{\sqrt 3}=\frac{\sqrt 3}{3}$
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