Precalculus (6th Edition)

Published by Pearson
ISBN 10: 013421742X
ISBN 13: 978-0-13421-742-0

Chapter 7 - Trigonometric Identities and Equations - 7.1 Fundamental Identities - 7.1 Exercises - Page 658: 22

Answer

$-\dfrac {5}{8}$

Work Step by Step

$csc\theta =\dfrac {1}{\sin \theta }=-\dfrac {8}{5}\Rightarrow \sin \theta =\dfrac {1}{-\dfrac {8}{5}}=-\dfrac {5}{8}$
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