#### Answer

negative

#### Work Step by Step

RECALL:
The quadrantal angles are:
Positive x-axis: $0$ radians;
Positive y-axis: $\frac{3.14}{2} = 1.57$ radians;
Negative x-axis: $3.14$ radians;
Negative y-axis: $4.61$ radians
Positive x-axis: $6.18$ radians
Thus, when moving counterclockwise from the positive x-axis, the angle $5$ radians is beyond the negative y-axis but before the positive x-axis.
This means that the angle is in Quadrant IV.
With $\sin{\theta}=y$, and since the value of $y$ is negative in Quadrant IV, then $\sin{5}$ must be negative.