Chapter 6 - The Circular Functions and Their Graphs - 6.2 The Unit Circle and Circular Functions - 6.2 Exercises: 5

$1$

Work Step by Step

$\frac{\pi}{4}=60^o$ is a special angle that intersects the unit circle at the point $(\frac{\sqrt2}{2}, \frac{\sqrt3}{2})$. Since $\tan{\theta}=\frac{y}{x}$, then $\tan{\frac{\pi}{4}} =\dfrac{\frac{\sqrt2}{2}}{\frac{\sqrt2}{2}}=1$

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