Precalculus (6th Edition)

Published by Pearson
ISBN 10: 013421742X
ISBN 13: 978-0-13421-742-0

Chapter 6 - The Circular Functions and Their Graphs - 6.2 The Unit Circle and Circular Functions - 6.2 Exercises: 3

Answer

$\sin{\frac{\pi}{4}} =\frac{\sqrt2}{2}$

Work Step by Step

$\frac{\pi}{4}$ is a special angle that intersects the unit circle at the point $(\frac{\sqrt2}{2}, \frac{\sqrt2}{2})$. Since $\sin{\theta}=y$, then $\sin{\frac{\pi}{4}} =\frac{\sqrt2}{2}$
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