Precalculus (6th Edition)

Published by Pearson
ISBN 10: 013421742X
ISBN 13: 978-0-13421-742-0

Chapter 5 - Trigonometric Functions - 5.1 Angles - 5.1 Exercises - Page 503: 8

Answer

$\left( 12\dfrac {1}{2}\right) ^{0}$

Work Step by Step

Becouse one minute is one sixtyth of one degree $12^{0}30'=12^{0}+\left( \dfrac {1}{60}\times 30\right) ^{0}=12^{0}+\dfrac {1^{0}}{2}=\left( 12\dfrac {1}{2}\right) ^{0}$
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