Precalculus (6th Edition)

Published by Pearson
ISBN 10: 013421742X
ISBN 13: 978-0-13421-742-0

Chapter 5 - Trigonometric Functions - 5.1 Angles - 5.1 Exercises - Page 503: 21

Answer

(a) $69^\circ 49'30''$ (b) $159^\circ 49'30''$

Work Step by Step

(a) For the complement, we have $\alpha=90^\circ-20^\circ 10'30''=89^\circ59'60''-20^\circ 10'30''=69^\circ 49'30''$ (b) For the supplement, we have $\beta=180^\circ-20^\circ 10'30''=179^\circ59'60''-20^\circ 10'30''=159^\circ 49'30''$
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