Answer
$42.7\ ^\circ C$
Work Step by Step
Step 1. State the model equation $A(t)=10e^{0.0095t}$
Step 2. For $A(t)=15\ g$, we have $15=10e^{0.0095t}$, thus $t=\frac{1}{0.0095}ln(\frac{3}{2})\approx42.7\ ^\circ C$
Precalculus (6th Edition)
by Lial, Margaret L.; Hornsby, John; Schneider, David I.; Daniels, Callie
Published by
Pearson
ISBN 10:
013421742X
ISBN 13:
978-0-13421-742-0
Chapter 4 - Inverse, Exponential, and Logarithmic Functions - 4.6 Applications and Models of Exponential Growth and Decay - 4.6 Exercises - Page 480: 26
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