Precalculus (6th Edition)

Published by Pearson
ISBN 10: 013421742X
ISBN 13: 978-0-13421-742-0

Chapter 4 - Inverse, Exponential, and Logarithmic Functions - 4.6 Applications and Models of Exponential Growth and Decay - 4.6 Exercises - Page 480: 24

Answer

$4200\ yr$

Work Step by Step

Step 1. State the model equation $A(t)=A_0e^{-0.0001216t}$ (textbook page 476) Step 2. Given $A(t)=0.6A_0$, we have $0.6A_0=A_0e^{-0.0001216t}$, thus $t=\frac{1}{-0.0001216}ln(0.6)\approx4200\ yr$
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