Answer
$4200\ yr$
Work Step by Step
Step 1. State the model equation $A(t)=A_0e^{-0.0001216t}$ (textbook page 476)
Step 2. Given $A(t)=0.6A_0$, we have $0.6A_0=A_0e^{-0.0001216t}$, thus $t=\frac{1}{-0.0001216}ln(0.6)\approx4200\ yr$
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