#### Answer

$\dfrac {2}{3}$

#### Work Step by Step

$x=\log _{4}\sqrt [3] {16}\Rightarrow 4^{x}=\sqrt [3] {16}\Rightarrow 4^{x}=\sqrt [3] {4^{2}}\Rightarrow 4^{x}=4^{\dfrac {2}{3}}\Rightarrow x=\dfrac {2}{3}$

Published by
Pearson

ISBN 10:
013421742X

ISBN 13:
978-0-13421-742-0

$\dfrac {2}{3}$

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