Precalculus (6th Edition)

Published by Pearson
ISBN 10: 013421742X
ISBN 13: 978-0-13421-742-0

Chapter 4 - Inverse, Exponential, and Logarithmic Functions - 4.3 Logarithmic Functions - 4.3 Exercises - Page 445: 23

Answer

$\dfrac {1}{4}$

Work Step by Step

$x=\log _{8}\sqrt [4] {8}\Rightarrow 8^{x}=\sqrt [4] {8}\Rightarrow 8^{x}=8^{\dfrac {1}{4}}\Rightarrow x=\dfrac {1}{4}$
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