Precalculus (6th Edition)

Published by Pearson
ISBN 10: 013421742X
ISBN 13: 978-0-13421-742-0

Chapter 4 - Inverse, Exponential, and Logarithmic Functions - 4.3 Logarithmic Functions - 4.3 Exercises - Page 444: 5



Work Step by Step

$\log_{x}\frac{16}{81}=2$ means that x must be raised to the power of 2 to get $\frac{16}{81}$. $x^2=\frac{16}{81}$ $x=\sqrt{\frac{16}{81}}$ $x=\frac{4}{9}$ $x=\frac{2}{3}$
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