Precalculus (6th Edition)

Published by Pearson
ISBN 10: 013421742X
ISBN 13: 978-0-13421-742-0

Chapter 4 - Inverse, Exponential, and Logarithmic Functions - 4.3 Logarithmic Functions - 4.3 Exercises - Page 444: 1

Answer

(a) to C. (b) to A. (c) to E. (d) to B. (e) to F. (f) to D.

Work Step by Step

(a) to C. $log_216=4$ because $2^4=16$ (b) to A. $log_31=0$ because $3^0=1$ (c) to E. $log_{10}0.1=-1$ because $10^{-1}=0.1$ (d) to B. $log_2\sqrt 2=\frac{1}{2}$ because $2^{1/2}=\sqrt 2$ (e) to F. $log_e(\frac{1}{e^2})=-2$ because $e^{-2}=\frac{1}{e^2}$ (f) to D. $log_{\frac{1}{2}}(8)=-3$ because $(\frac{1}{2})^{-3}=8$
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