Precalculus (6th Edition)

Published by Pearson
ISBN 10: 013421742X
ISBN 13: 978-0-13421-742-0

Chapter 2 - Graphs and Functions - Chapter 2 Test Prep - Review Exercises - Page 299: 112

Answer

$2x+h-5$

Work Step by Step

Step 1. Given $f(x)=x^2-5x+3$, we have $f(x+h)=(x+h)^2-5(x+h)+3=x^2+2xh+h^2-5x-5h+3$ Step 2. $f(x+h)-f(x)=x^2+2xh+h^2-5x-5h+3-(x^2-5x+3)=2xh+h^2-5h$ Step 3. Thus $\frac{f(x+h)-f(x)}{h}=2x+h-5$
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