Answer
$2x+h-5$
Work Step by Step
Step 1. Given $f(x)=x^2-5x+3$, we have $f(x+h)=(x+h)^2-5(x+h)+3=x^2+2xh+h^2-5x-5h+3$
Step 2. $f(x+h)-f(x)=x^2+2xh+h^2-5x-5h+3-(x^2-5x+3)=2xh+h^2-5h$
Step 3. Thus $\frac{f(x+h)-f(x)}{h}=2x+h-5$
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