Answer
$\color{blue}{\bf{ 44 }}$
Work Step by Step
We are given the two functions $\bf{f}$ and $\bf{g}$
$\bf{f(x) = 3x^2 - 4 }$ and $\bf{g(x) = x^2 - 3x - 4 }$
We are asked to find $\bf{ ( f-g )(4) }$
$( f -g )(4) = 3(4^2) - 4-(4^2 - 3(4) - 4) $
$3(16) - 4-(16 - 12 - 4) $
$48- 4 -0 $
$\color{blue}{\bf{ 44 }}$
