#### Answer

$B$

#### Work Step by Step

Solve for $y$ to obtain:
$4x+3y=12
\\4x+3y-4x=12-4x
\\3y=-4x+12
\\\frac{3y}{3}=\frac{-4x+12}{3}
\\y=\frac{-4}{3}+4$
The slope of this line is $\frac{-4}{3}$.
RECALL:
The slope can be interpreted as the ratio of the rise (change in $y$) over run (change in $x$).
The given equation has a slope of $\dfrac{-4}{3}$.
This means that the rise is $-4$ units and the run is $3$ units.
Notice for the graph in Option $B$, from the point $(0, 4)$ to the point $(3, 0)$, there is a rise of $-4$ unit and a run of $3$ units. Thus, its slope is $\dfrac{-4}{3}$.
Therefore, the graph of the given equation is the one in Option $B$.