## Precalculus (6th Edition)

$4$; $3$
RECALL: The point-s[ope form of a line's equation is $y-y_1=m(x-x-1)$ where $m$=slope and $(x_1, y_1)$ is a point on the line. Thus, the line whose equation is $y-3=4(x-8)$ has a slope of $4$ and contains the point $(8, 3)$. Therefore, the missing expressions in the given statement (in order), are: $4$; $3$