Precalculus (6th Edition)

Published by Pearson
ISBN 10: 013421742X
ISBN 13: 978-0-13421-742-0

Chapter 2 - Graphs and Functions - 2.4 Linear Functions - 2.4 Exercises: 89

Answer

The sum of the results in Exercises 86 and 87 is equal to the result in Exercise 88.

Work Step by Step

The results in Exercises 86 and 87 are $\sqrt{10}$ and $2\sqrt{10}$, respectively. Thus, their sum is: sum $=\sqrt{10} + 3\sqrt{10} = 3\sqrt{10}$ The result in Exercise 89 is $3\sqrt{10}$. Therefore, the distance from the 1st point to the 4th point is equal to the sum of the distance between the first two points and the distance between the 2nd and the 4th point.
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.