## Precalculus (6th Edition)

The distance between the first two points is $\sqrt{10}$ units.
RECALL: The distance $d$ between the points $(x_1, y_1)$ and $(x_2, y_2)$ is given by the formula $d=\sqrt{(x_1-x_2)^2+(y_1-y_2)^2}$ Use the formula above to obtain: $d=\sqrt{0-1)^2+(-6-(-3))^2} \\d=\sqrt{(-1)^2+(-6+3)^2} \\d=\sqrt{1+(-3)^2} \\d=\sqrt{1+9} \\d=\sqrt{10}$