## Precalculus (6th Edition)

slope $=0$
RECALL: The slope $m$ of the line that passes through the points $(x_1, y_1)$ and $(x_2, y_2)$ is given by the formula $m=\dfrac{y_2-y_1}{x_2-x_1}$ Use the formula above to solve for the slope and obtain: $m=\dfrac{4-4}{6-(-2)}=\dfrac{0}{6+2}=\dfrac{0}{8}=0$