#### Answer

$\dfrac {5}{4}=1.25$

#### Work Step by Step

$\sum ^{\infty }_{i=1}\left( \dfrac {5}{9}\right) ^{i}=\dfrac {a_{1}}{1-r};a_{1}=\left( \dfrac {5}{9}\right) ^{1}=\dfrac {5}{9};r=\dfrac {5}{9}\Rightarrow S_{\infty }=\dfrac {a_{1}}{1-r}=\dfrac {\dfrac {5}{9}}{1-\dfrac {5}{9}}=\dfrac {5}{4}=1.25$