Precalculus (6th Edition)

Published by Pearson
ISBN 10: 013421742X
ISBN 13: 978-0-13421-742-0

Chapter 11 - Further Topics in Algebra - 11.3 Geometric Sequences and Series - 11.3 Exercises - Page 1035: 56


$\dfrac {8}{3}$

Work Step by Step

$r=\dfrac {\dfrac {1}{3}}{\dfrac {2}{3}}=\dfrac {\dfrac {2}{3}}{\dfrac {4}{3}}=\dfrac {1}{2}\Rightarrow S_{\infty }=\dfrac {a_{1}}{1-r}=\dfrac {\dfrac {4}{3}}{1-\dfrac {1}{2}}=\dfrac {8}{3}$
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