#### Answer

$\dfrac {8}{3}$

#### Work Step by Step

$r=\dfrac {\dfrac {1}{3}}{\dfrac {2}{3}}=\dfrac {\dfrac {2}{3}}{\dfrac {4}{3}}=\dfrac {1}{2}\Rightarrow S_{\infty }=\dfrac {a_{1}}{1-r}=\dfrac {\dfrac {4}{3}}{1-\dfrac {1}{2}}=\dfrac {8}{3}$

Published by
Pearson

ISBN 10:
013421742X

ISBN 13:
978-0-13421-742-0

$\dfrac {8}{3}$

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