Precalculus (6th Edition)

Published by Pearson
ISBN 10: 013421742X
ISBN 13: 978-0-13421-742-0

Chapter 11 - Further Topics in Algebra - 11.2 Arithmetic Sequences and Series - 11.2 Exercises - Page 1025: 64

Answer

$${a_1} = - 10,\,\,\,\,d = 3$$

Work Step by Step

$$\eqalign{ & {S_{25}} = 650,\,\,\,{a_{25}} = 62 \cr & {\text{Use the first formula for }}{S_n} \cr & {S_n} = \frac{n}{2}\left( {{a_1} + {a_n}} \right) \cr & {\text{Let }}n = 25 \cr & {S_{25}} = \frac{{25}}{2}\left( {{a_1} + {a_{25}}} \right) \cr & 650 = \frac{{25}}{2}\left( {{a_1} + 62} \right) \cr & {\text{Solve for }}{a_1} \cr & 52 = {a_1} + 62 \cr & {a_1} = - 10 \cr & \cr & {\text{Now find }}d,{\text{ use the formula for the }}n{\text{th term}} \cr & {a_n} = {a_1} + \left( {n - 1} \right)d \cr & {a_{25}} = {a_1} + \left( {25 - 1} \right)d \cr & 62 = - 10 + \left( {24} \right)d \cr & 72 = 24d \cr & d = 3 \cr & \cr & {\text{Then,}} \cr & {a_1} = - 10,\,\,\,\,d = 3 \cr} $$
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