Precalculus (6th Edition)

Published by Pearson
ISBN 10: 013421742X
ISBN 13: 978-0-13421-742-0

Chapter 11 - Further Topics in Algebra - 11.2 Arithmetic Sequences and Series - 11.2 Exercises - Page 1025: 57

Answer

$${S_{50}} = 2500$$

Work Step by Step

$$\eqalign{ & {\text{The first }}50{\text{ positive odd integers form the arithmetic sequence }} \cr & {\text{1}},3,{\text{5}},{\text{7}},{\text{9}},{\text{ }}.{\text{ }}.{\text{ }}.{\text{ }}, \cr & {a_1} = 1,\,\,\,\,d = 2,\,\,\,n = 50 \cr & {\text{The formula of the sequence is}} \cr & {a_n} = {a_1} + \left( {n - 1} \right)d \cr & {a_{50}} = 1 + \left( {50 - 1} \right)\left( 2 \right) \cr & {a_{50}} = 99 \cr & \cr & {\text{Let }}{a_1} = 1,\,\,{a_{50}} = 99,\,\,n = 50 \cr & {\text{Using the formula }}{S_n} = \frac{n}{2}\left( {{a_1} + {a_n}} \right) \cr & {S_{50}} = \frac{{50}}{2}\left( {1 + 99} \right) \cr & {S_{50}} = 25\left( {100} \right) \cr & {S_{50}} = 2500 \cr} $$
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