Precalculus (6th Edition)

Published by Pearson
ISBN 10: 013421742X
ISBN 13: 978-0-13421-742-0

Chapter 1 - Equations and Inequalities - Chapter 1 Test Prep - Review Exercises - Page 175: 5



Work Step by Step

Multiply $B(p+1)$ to both sides of the equation to obtain: $$\require{cancel} \\A(B(p+1))=\dfrac{24f}{B(p+1)} \cdot B(p+1) \\\\AB(p+1)=\dfrac{24f}{\cancel{B(p+1)}} \cdot \cancel{B(p+1)} \\AB(p+1)=24f$$ Divide $24$ to both sides to obtain: $$\dfrac{AB(p+1)}{24}=\dfrac{24f}{24} \\\dfrac{AB(p+1)}{24}=f$$
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